In Fig. 6.51 we see two concentric circles with a common centre O - End-of-Chapter Exercises

part 2 - Question 23 - End-of-Chapter Exercises - Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar - Class 9
part 3 - Question 23 - End-of-Chapter Exercises - Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar - Class 9 part 4 - Question 23 - End-of-Chapter Exercises - Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar - Class 9 part 5 - Question 23 - End-of-Chapter Exercises - Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar - Class 9 part 6 - Question 23 - End-of-Chapter Exercises - Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar - Class 9

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Question 23 In Fig. 6.51 we see two concentric circles with a common centre O. A chord BC of the larger circle is drawn, touching the smaller circle at A. The length of BC is ๐‘™. Show that the area of the green region enclosed between the two circles is 1/4 ๐œ‹๐‘™^2. Letโ€™s answer this step by step Problem 23: Concentric Circles Find the area of the green region enclosed between two concentric circles. 1 Here we have two concentric circles (circles with the common center O ). The green ring is the area we want to find. Problem 23: Concentric Circles Find the area of the green region enclosed between two concentric circles. 2 Let the radius of the large circle be and the small circle be . The area of the green ring is Area Problem 23: Concentric Circles Find the area of the green region enclosed between two concentric circles. 3 A chord BC of length is drawn on the large circle, touching the small circle at point A. This means is a tangent to the small circle. Problem 23: Concentric Circles Find the area of the green region enclosed between two concentric circles. 4 Draw a line from center O to point A. A radius drawn to a tangent is always perpendicular . So, and .Problem 23: Concentric Circles Find the area of the green region enclosed between two concentric circles. 5 Draw a line from to . This is the radius of the large circle, so . We now have a right-angled triangle OAB . Problem 23: Concentric Circles Find the area of the green region enclosed between two concentric circles. 6 A perpendicular line from the center to a chord bisects (cuts in half) the chord. This means is exactly half of . So, Problem 23: Concentric Circles Find the area of the green region enclosed between two concentric circles. 7 Let's use the Pythagorean theorem on triangle OAB: Base ^2+ Height ^2= Hypotenuse ^2. This gives us: (I/2)^2+r^2=R^2 Problem 23: Concentric Circles Find the area of the green region enclosed between two concentric circles. 8 Let's rearrange this equation by subtracting r^2 from both sides: R^2-r^2=(l/2)^2=l^2/4. Problem 23: Concentric Circles Find the area of the green region enclosed between two concentric circles. 9 Remember our area formula from Step 2? Area =ฮ (R^2-r^2 ). Substituting what we just found, we get: Area =n(l^2/4)=1/4ฯ€l^2. Proved! Proof Complete! Great job!

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