Question 8 - End-of-Chapter Exercises - Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar
Last updated at June 3, 2026 by Teachoo
End-of-Chapter Exercises
Question 1
Important
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Class 9
Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar
- Definition (and Quesitons)
- Perimeter of Different Shapes
- Perimeter of a Circle - C/D Ratio
- Pi is Irrational
- Length of an Arc of a Circle
- Problems, Puzzles, and Paradoxes on Perimeter
- Exercise Set 6.1
- Area of Square & Rectangle
- Area of a Parallelogram
- Area of a Triangle
- Heron's Formula
- Circumcircle and Incircle of a Triangle
- Brahmaguptaβs Formula for the Area of a Cyclic 4-gon
- Squaring a Rectangle
- Exercise Set 6.2
- Area of a circle
- Exercise Set 6.3
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End-of-Chapter Exercises
Transcript
Question 8 Find the area of a quadrant of a circle whose circumference is 66 cm. Quadrant is ΒΌth of a circle So, we can write Area of quadrant = 1/4Γ area of circle = π/π π π^π We need to find r It is given that Circumference = 2Οr 66 = 2Οr 66 = 2 Γ 22/7 Γ r 66 = 44/7 Γ r 66 Γ 7/44 = r 3 Γ 7/2 = r 21/2 = r r = ππ/π cm Now, Area of quadrant = 1/4 ππ^2 = π/π Γππ/π Γ (ππ/π)^π = 1/4 Γ22/7 Γ21/2 Γ21/2 = 1/2 Γ11/7 Γ21/2 Γ21/2 = (11 Γ 21 Γ 21)/(2 Γ 2 Γ 2 Γ 7) = 4851/56 = 86.625 cm2
