Heron's Formula - Examples, Video [Chapter 3 Class 9 Ganita Manjari] - Heron's Formula

part 2 - Heron's Formula - Heron's Formula - Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar - Class 9
part 3 - Heron's Formula - Heron's Formula - Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar - Class 9

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Transcript

Heron's Formula Heron's Formula is way to find Area of Triangle when sides are given Area of Triangle = √(𝒔 (π’”βˆ’π’‚)(π’”βˆ’π’ƒ)(π’”βˆ’π’„)) Where s = Semi-perimeter = (𝒂 + 𝒃 + 𝒄)/𝟐 Let’s do an example Find Area of triangle with sides 9, 11 and 16 Given a = 9, b = 11, c = 16 Here, s = (𝒂 + 𝒃 + 𝒄)/𝟐 = (9 + 11 + 16)/2 = 18 Now , Area of Triangle = √(𝑠 (π‘ βˆ’π‘Ž)(π‘ βˆ’π‘)(π‘ βˆ’π‘)) = √(πŸπŸ– (πŸπŸ–βˆ’πŸ—) Γ— (πŸπŸ–βˆ’πŸπŸ) Γ— (πŸπŸ–βˆ’πŸπŸ”)) = √(18 Γ— 9 Γ— 7 Γ— 2) = √(36 Γ— 9 Γ— 7) = √36 Γ— √9 Γ—βˆš7 = 6 Γ— 3 Γ— √7 = 18βˆšπŸ• square units

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