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Ex 6.2, 1
Last updated at May 31, 2026 by Teachoo
Class 9
Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar
- Definition (and Quesitons)
- Perimeter of Different Shapes
- Perimeter of a Circle - C/D Ratio
- Pi is Irrational
- Length of an Arc of a Circle
- Problems, Puzzles, and Paradoxes on Perimeter
- Exercise Set 6.1
- Area of Square & Rectangle
- Area of a Parallelogram
- Area of a Triangle
- Heron's Formula
- Circumcircle and Incircle of a Triangle
- Brahmagupta’s Formula for the Area of a Cyclic 4-gon
- Squaring a Rectangle
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Exercise Set 6.2
Transcript
Ex 6.2, 1 Find the area of triangle ADE in Fig. 6.31. We can use formula Area of Triangle = 𝟏/𝟐 × Base × Height Her, base is AD Let’s draw height So, Height is EN Now, EN is equal to length of the rectangle ABCD ∴ EN = 10 cm And, Breadth of rectangle is equal ∴ AD = BC = 8 cm Now, Area ∆ AED = 1/2 × Base × Height = 1/2 × AD × EN = 𝟏/𝟐 × 8 × 10 = 4 × 10 = 40 cm2
