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Ex 6.2, 5
Last updated at May 31, 2026 by Teachoo
Class 9
Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar
- Definition (and Quesitons)
- Perimeter of Different Shapes
- Perimeter of a Circle - C/D Ratio
- Pi is Irrational
- Length of an Arc of a Circle
- Problems, Puzzles, and Paradoxes on Perimeter
- Exercise Set 6.1
- Area of Square & Rectangle
- Area of a Parallelogram
- Area of a Triangle
- Heron's Formula
- Circumcircle and Incircle of a Triangle
- Brahmagupta’s Formula for the Area of a Cyclic 4-gon
- Squaring a Rectangle
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Exercise Set 6.2
Transcript
Ex 6.2, 5 One diagonal of a rhombus is twice as long as the other diagonal. If the rhombus has area 128 cm2, find the length of the shorter diagonal. Given that One diagonal of a rhombus is twice as long as the other diagonal Let First diagonal = d cm Thus, Second Diagonal = 2d cm Now, we know that Area of rhombus = 1/2 × d1 × d2 128 = 𝟏/𝟐 × d × 2d 128 = d × d 128 = d2 d2 = 128 d = √128 d = √(64 × 2) d = √(8^2 × 2) d = √(8^2 ) ×√2 d = 𝟖√𝟐 cm Thus, length of shorter diagonal is 𝟖√𝟐 cm
