Squaring a Rectangle - Finding Area with Square Units [with Examples] - Squaring a Rectangle

part 2 - Squaring a Rectangle - Squaring a Rectangle - Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar - Class 9
part 3 - Squaring a Rectangle - Squaring a Rectangle - Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar - Class 9 part 4 - Squaring a Rectangle - Squaring a Rectangle - Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar - Class 9 part 5 - Squaring a Rectangle - Squaring a Rectangle - Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar - Class 9 part 6 - Squaring a Rectangle - Squaring a Rectangle - Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar - Class 9 part 7 - Squaring a Rectangle - Squaring a Rectangle - Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar - Class 9 part 8 - Squaring a Rectangle - Squaring a Rectangle - Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar - Class 9 part 9 - Squaring a Rectangle - Squaring a Rectangle - Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar - Class 9

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Transcript

Squaring a Rectangle Squaring a Rectangle means Given a rectangle, we construct a square of equal area We convert Rectangle ABCD into a square Let’s look at it step-by-step Why this method works? Consider the right angled ∆HKP (highlighted in yellow above). Using the Baudhāyana-Pythagoras theorem we get: 𝐻𝑃^2=𝐻𝐾^2−𝐵𝐻^2 𝑯𝑷^𝟐=((𝒂 + 𝒃)/𝟐)^𝟐−((𝒂 − 𝒃)/𝟐)^𝟐 𝐻𝑃^2=(𝑎^2+2𝑎𝑏+𝑏^2)/4−(𝑎^2−2𝑎𝑏+𝑏^2)/4 𝐻𝑃^2 =4𝑎𝑏/4 𝑯𝑷^𝟐 =𝒂𝒃 Therefore, square HPQS has the same area as rectangle ABCD!

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