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Question 15 Show that if a rectangle is inscribed in a circle, then the point of intersection of its diagonals must lie at the centre of the circle. Given: A circle with center O ABCD is a rectangle inscribed in a circle with diagonals AC & BD To prove: Diagonals AC & BD intersect at center O Proof: Let’s look at diagonal AC & ∠ B Here, we have chord AC, making ∠ ABC = 90° at point B on circle Since chord AC makes a 90° angle at any point of the circle Thus, AC must be the diameter Because angle in a semi-circle is a right angle Since AC is the diameter, it must pass through center O Similarly, we can say Chrod BD makes ∠ A = 90° on the circle So, BD is the diameter, and passes through center O Thus, both diagonals AC & BD pass through center O Hence proved

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Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

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