You are here
![Mid-points and Perpendicular Bisectors of Chords [Ganita Class 9] - Mid-points and Perpendicular Bisectors of Chords](https://cdn.teachoo.com/6d213dca-4e1d-453f-8ac0-4a9360e2be1c/slide3.jpg)
Proof is here
Mid-points and Perpendicular Bisectors of Chords
Last updated at May 26, 2026 by Teachoo
Mid-points and Perpendicular Bisectors of Chords
Class 9
Chapter 5 Class 9 - I’m Up and Down, and Round and Round (Ganita Manja
- Definitions
- Symmetries of Circle
- Number of Circles
- Exercise Set 5.1
- Think, Draw and Infer (Page 98)
- Angle Subtended by Chords
- Exercise Set 5.2
-
Mid-points and Perpendicular Bisectors of Chords
- Exercise Set 5.3
- Distance of Chords from the Centre
- Exercise Set 5.4
- Distance of unequal chords from center
- Exercise Set 5.5
- Angle subtended by an arc
- Exercise Set 5.6
- Concyclicity of Points and Cyclic Quadrilateral
- Theorems (and their Proofs)
- End-of-Chapter Exercises
Transcript
Mid-points and Perpendicular Bisectors of Chords Let’s consider this diagram Here, we have Chord AB M is the mid-point of the chord OM is line joining center of circle to the mid-point of chord Now, we have two theorems on this Let’s look at the Proof Proof is here Theorem 4 of Chapter 5 Class 9 – Ganita Manjari Part 1 Theorem 5 of Chapter 5 Class 9 – Ganita Manjari Part 1 Theorem 4 "The line joining the centre of a circle and the midpoint of a chord is perpendicular to the chord." Theorem 5 (The Converse) "The perpendicular from the centre of a circle to a chord bisects the chord." GIVEN: PROVE:
