Question 13 - End-of-Chapter Exercises - Chapter 5 Class 9 - I’m Up and Down, and Round and Round (Ganita Manja

Transcript

Question 13 Draw a circle in which a chord of 6 cm length stands at a distance of 3 cm from the centre. (Hint: Is it a circumcircle of a suitable triangle?) Let’s draw a rough diagram Here, radius of circle and center is not given Now, we follow these steps Draw chord AB = 6 cm Mark mid-point M (As perpendicular from center bisects the chord and OM ⊥ AB) Locate center O by making OM ⊥ AB and OM = 3 cm Taking OA as radius, draw a circle Steps of construction 1. Draw a line segment AB of length 6 cm 2. Now, making perpendicular bisector of AC Taking point A as center, radius more than ½ AB, we draw an arc on top and bottom of AB. Doing same for point B Join points where the two arcs intersect. This is perpendicular bisector of AB 3. Mark point M where Perpendicular bisector intersects AB 4. Since OM = 3 cm. Measure 3 cm along the perpendicular line from 'M' and mark point 'O'. 5. With 'O' as the center and 'OA' (or 'OB') as the radius, draw the required circle. This is the circumcircle of △AOB