Ex 9.3, 14 - Chapter 9 Class 12 Differential Equations
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 9.3, 14 For each of the differential equations in Exercises 11 to 14, find a particular solution satisfying the given condition : ππ¦/ππ₯=π¦ tanβ‘ π₯;π¦=1 When π₯=0 ππ¦/ππ₯=π¦ tanβ‘ x π π/π=γπππ§ π± ππ±γβ‘ Integrating both sides β«1βππ¦/π¦ = β«1βtanβ‘γπ₯ ππ₯γ log |π| = log |π¬ππβ‘π |+πππβ‘π log |π¦| = log (c sec x) y = c sec x (β΅ log π + log b = log πb) Put x = 0 and y = 1 1 = C Sec 0 1 = C Γ 1 C = 1 Put value of C in (1) y = 1 Γ sec x y = sec x
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