Last updated at Dec. 16, 2024 by Teachoo
Ex 9.3, 3 For each of the differential equations in Exercises 1 to 10, find the general solution : ๐๐ฆ/๐๐ฅ+๐ฆ=1(๐ฆโ 1) ๐๐ฆ/๐๐ฅ+๐ฆ=1 ๐๐ฆ/๐๐ฅ=1โ๐ฆ ๐๐ฆ = (1 โ y) dx ๐๐ฆ/(1 โ ๐ฆ) = dx ๐ ๐/(๐ โ ๐) = โdx Integrating both sides. โซ1โใ๐๐ฆ/(๐ฆ โ 1)=ใ โซ1โใโ๐๐ฅใ log (y โ 1) = โx + C y โ 1 = e(โx + C) y โ 1 = eโx ร eC y = eโx ร eC + 1 Putting eC = A y = Aeโx + 1 is the general solution
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo