1. Chapter 6 Class 12 Application of Derivatives
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  3. Tangents and Normals (using Differentiation)
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Question 26 (MCQ) - Tangents and Normals (using Differentiation) - Chapter 6 Class 12 Application of Derivatives

Last updated at Dec. 16, 2024 by Teachoo

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Question 26 The slope of the normal to the curve y = 2x2 + 3 sin x at x = 0 is (A) 3 (B) 1/3 (C) – 3 (D) – 1/3Slope of tangent is 𝑑𝑦/𝑑π‘₯ 𝑦=2π‘₯^2+3 sin⁑π‘₯ Differentiating w.r.t. π‘₯ 𝑑𝑦/𝑑π‘₯=𝑑(2π‘₯^2 +3 sin⁑π‘₯ )/𝑑π‘₯ 𝑑𝑦/𝑑π‘₯=4π‘₯+3 cos⁑π‘₯ We know that Slope of tangent Γ— Slope of Normal =βˆ’1 (4π‘₯+3 cos⁑π‘₯ ) Γ— Slope of Normal =βˆ’1 Slope of Normal = (βˆ’1)/(4π‘₯ + 3 cos⁑π‘₯ ) We need to find Slope of Normal at π‘₯=0 At x = 0 Slope of Normal =(βˆ’ 1 )/(4(0) + 3 cos⁑〖0Β°γ€— ) =(βˆ’1)/(0 + 3(1) )=(βˆ’1)/( 3) Hence, Correct Answer is D
  1. Chapter 6 Class 12 Application of Derivatives
  2. Serial order wise

    3. Tangents and Normals (using Differentiation)

    Approximations (using Differentiation) →
Approximations (using Differentiation) →
Chapter 6 Class 12 Application of Derivatives
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo