1. Chapter 6 Class 12 Application of Derivatives
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Question 3 - Tangents and Normals (using Differentiation) - Chapter 6 Class 12 Application of Derivatives

Last updated at Dec. 16, 2024 by Teachoo

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Question 3 Find the slope of the tangent to curve ๐‘ฆ=๐‘ฅ^3โˆ’๐‘ฅ+1 at the point whose ๐‘ฅโˆ’๐‘๐‘œ๐‘œ๐‘Ÿ๐‘‘๐‘–๐‘›๐‘Ž๐‘ก๐‘’ is 2. ๐‘ฆ=๐‘ฅ^3โˆ’๐‘ฅ+1 We know that slope of tangent is ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ=๐‘‘(๐‘ฅ^3 โˆ’ ๐‘ฅ + 1)/๐‘‘๐‘ฅ ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ=3๐‘ฅ^2โˆ’1+0 We need to find ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ at the point whose ๐‘ฅโˆ’๐‘๐‘œ๐‘œ๐‘Ÿ๐‘‘๐‘–๐‘›๐‘Ž๐‘ก๐‘’ is 2 Putting ๐‘ฅ=2 in ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ ใ€–๐‘‘๐‘ฆ/๐‘‘๐‘ฅโ”‚ใ€—_(๐‘ฅ = 2)=3(2)^2โˆ’1 =3 ร—4โˆ’1 =12โˆ’1 =11 Hence slope of a tangent is 11
  1. Chapter 6 Class 12 Application of Derivatives
  2. Serial order wise

    3. Tangents and Normals (using Differentiation)

    Approximations (using Differentiation) →
Approximations (using Differentiation) →
Chapter 6 Class 12 Application of Derivatives
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo