Last updated at Dec. 16, 2024 by Teachoo
Ex 3.3, 22 Prove that cot ๐ฅ cot 2๐ฅ โ cot 2๐ฅ cot 3๐ฅ โ cot 3๐ฅ cot ๐ฅ = 1 Solving L.H.S. cot x cot 2x โ cot 2x cot 3x โ cot 3x cot x = cot x cot 2x โ cot 3x (cot 2x + cot x) = cot x cot 2x โ cot (2x + x) (cot 2x + cot x) = cot x cot 2x โ ((cot 2x cot x โ 1)/(cot x + cot 2x)) (cot 2x + cot x) = cot x cot 2x โ (cot 2x cot x โ 1) = cot x cot 2x โ cot 2x cot x + 1 = 1 = R.H.S. Hence L.H.S = R.H.S Hence proved
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo