

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Examples
Example 1 (ii) Important
Example 1 (iii) Important
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Example 20 You are here
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Question 1 Deleted for CBSE Board 2024 Exams
Question 2 Deleted for CBSE Board 2024 Exams
Question 3 Important Deleted for CBSE Board 2024 Exams
Question 4 Deleted for CBSE Board 2024 Exams
Question 5 Deleted for CBSE Board 2024 Exams
Question 6 Deleted for CBSE Board 2024 Exams
Last updated at May 29, 2023 by Teachoo
Example 20 Find the particular solution of the differential equation log(ππ¦/ππ₯)=3π₯+4π¦ given that π¦=0 π€βππ π₯=0 log(ππ¦/ππ₯)=3π₯+4π¦ ππ¦/ππ₯ = e(3x + 4y) ππ¦/ππ₯ = e3x e4y Separating the variables ππ¦/π^4π¦ = e3x dx eβ4y dy = e3x dx Integrating both sides β«1βγπ^(β4π¦) ππ¦γ=β«1βπ^3π₯ ππ₯ π^(β4π¦)/(β4)=π^3π₯/3+πΆ 0=π^3π₯/3+π^(β4π¦)/4+πΆ π^3π₯/3 + π^(β4π¦)/4 + C = 0 (4π3π₯" + " 3π^(β4π¦))/12 + C = 0 (4π3π₯" + " 3π^(β4π¦) + 12πΆ)/12 " = 0" 4π^3π₯ + 3π^(β4π¦) + 12C = 0 Given y = 0 when x = 0 β¦(1) Putting x = 0 & y = 0 in (1) 4π^(3(0)) + 3π^(β4(0)) + 12C = 0 4π^0 + 3π^0 + 12C = 0 4 + 3 + 12C = 0 7 + 12C = 0 12C = β 7 C = (β7)/12 Putting value of C in (1) 4π^3π₯ + 3π^(β4π¦) + 12C = 0 4π^3π₯ + 3π^(β4π¦) + 12((β7)/12) = 0 ππ^ππ + ππ^(βππ) β 7 = 0