Example 8 - Find curve (-2 ,3), slope of tangent is 2x/y2 - Examples

part 2 - Example 8 - Examples - Serial order wise - Chapter 9 Class 12 Differential Equations

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Example 8 Find the equation of a curve passing through the point (āˆ’2 ,3), given that the slope of the tangent to the curve at any point (š‘„ , š‘¦) is 2š‘„/š‘¦^2 Slope of tangent = š‘‘š‘¦/š‘‘š‘„ ∓ š’…š’š/š’…š’™ = šŸš’™/š’ššŸ š‘¦2 dy = 2x dx Integrating both sides ∫1ā–’š’ššŸ š’…š’š= ∫1ā–’ć€–šŸš’™ š’…š’™ć€— š‘¦^3/3 = 2.š‘„^2/2 + C š‘¦^3/3 = š‘„^2 + C š‘¦^3 = 怖3š‘„ć€—^2+3š¶ š’š^šŸ‘ = ć€–šŸ‘š’™ć€—^šŸ+š‘ŖšŸ where š¶1 = 3C Given that equation passes through (āˆ’2, 3) Putting x = āˆ’2, y = 3 in (1) y3 = 3x2 + C1 33 = 3(āˆ’2)2 + C1 27 = 3 Ɨ 4 + C1 27 āˆ’ 12 = C1 15 = C1 C1 = 15 Putting C1 in (1) y3 = 3x2 + 15 y = "(3x2 + " 怖"15)" 怗^(šŸ/šŸ‘) " "is the particular solution of the equation.

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