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Last updated at March 16, 2023 by Teachoo
Example 10 Find the general solution of the differential equation ππ¦/ππ₯=(1 + π¦^2)/(1 + π₯^2 ) ππ¦/ππ₯=(1 + π¦^2)/(1 + π₯^2 ) ππ¦/(1 + π¦2)=ππ₯/(1 + π₯^2 ) Integrating both sides β«1βππ¦/(1 + π¦^2 ) = β«1βππ¦/(1 + π₯^2 ) (β«1β1/(1 + π₯^2 ) dx = tanβ1 x + c) tanβ1 y = tanβ1 x + c tanβ1 y = tanβ1 x + c is the general solution of the given equation