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Example 6 - Chapter 9 Class 12 Differential Equations
Last updated at Aug. 14, 2023 by Teachoo
Examples
Example 1 (i)
Example 1 (ii) Important
Example 1 (iii) Important
Example 2
Example 3 Important
Example 4
Example 5
Example 6 You are here
Example 7 Important
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Example 9 Important
Example 10 Important
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Example 12 Important
Example 13 Important
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Example 15 Important
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Example 17 Important
Example 18 Important
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Example 21 Important
Example 22 Important
Question 1 Deleted for CBSE Board 2024 Exams
Question 2 Deleted for CBSE Board 2024 Exams
Question 3 Important Deleted for CBSE Board 2024 Exams
Question 4 Deleted for CBSE Board 2024 Exams
Question 5 Deleted for CBSE Board 2024 Exams
Question 6 Deleted for CBSE Board 2024 Exams
Chapter 9 Class 12 Differential Equations
Serial order wise
Transcript
Example 6 Find the particular solution of the differential equation 𝑑𝑦/𝑑𝑥=−4𝑥𝑦^2 given that 𝑦=1 , 𝑤ℎ𝑒𝑛 𝑥=0Given differential equation , 𝑑𝑦/𝑑𝑥=−4𝑥𝑦^2 𝒅𝒚/𝒚^𝟐 = (−4 x) dx Integrating both sides. ∫1▒𝑑𝑦/𝑦^2 = ∫1▒〖−4𝑥 𝑑𝑥〗 ∫1▒𝒅𝒚/𝒚^𝟐 = −4 ∫1▒〖𝒙 𝒅𝒙〗 𝑦^(−2+1)/(−2+1) = −4.𝑥^2/2 + c − 𝟏/𝒚 = –2x2 + c y = (−1)/(−2𝑥2 + 𝑐) y = (−1)/(−(2𝑥2 − 𝑐)) y = 𝟏/(𝟐𝒙𝟐 − 𝒄) Given that at x = 0, y = 1 Putting x = 0, y = 1, in (1) 1 = 1/(2(0)^2 ) − c 1 = 1/(−𝐶) c = −1 Putting c = −1 in (1) y = 1/(2𝑥^2 ) −(−1) y = 𝟏/(𝟐𝒙^𝟐 + 𝟏) Hence, the particular solution of the equation is y = 𝟏/(𝟐𝒙^𝟐 + 𝟏)
