Example 11 - Chapter 9 Class 12 Differential Equations

Last updated at Dec. 24, 2018 by Teachoo

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Example 11 Find the particular solution of the differential equation 𝑑𝑦/𝑑𝑥=−4𝑥𝑦^2 given that 𝑦=1 , 𝑤ℎ𝑒𝑛 𝑥=0 Given differential equation , 𝑑𝑦/𝑑𝑥=−4𝑥𝑦^2 𝑑𝑦/𝑦^2 = (−4 x) dx Integrating both sides. ∫1▒𝑑𝑦/𝑦^2 = ∫1▒〖−4𝑥 𝑑𝑥〗 ∫1▒𝑑𝑦/𝑦^2 = −4 ∫1▒〖𝑥 𝑑𝑥〗 𝑦^(−2+1)/(−2+1) = −4.𝑥^2/2 + c 𝑦^(−1)/(−1) = −2x2 + c − 1/𝑦 = –2x2 + c y = (−1)/(−2𝑥2 + 𝑐) y = (−1)/(−(2𝑥2 − 𝑐)) y = 1/(2𝑥2 − 𝑐) Given that at x = 0, y = 1 Putting x = 0, y = 1, in (1) 1 = 1/(2(0)^2 ) − c 1 = 1/(−𝐶) c = −1 Put c = −1 in (1) y = 1/(2𝑥^2 ) −(−1) y = 1/(2𝑥^2 + 1) Hence, the particular solution of the equation is y = 𝟏/(𝟐𝒙^𝟐 + 𝟏)

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Chapter 9 Class 12 Differential Equations

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