Examples
Last updated at December 16, 2024 by Teachoo
Transcript
Example 4 Find the general solution of the differential equation šš¦/šš„=(š„+1)/(2āš¦) , (š¦ā 2)Given šš¦/šš„=(š„ + 1)/(2 ā š¦) (2 ā y) dy = (x + 1) dx Integrating both sides. ā«1āć(šāš)š š=ć ā«1ā(š+š)š š 2y ā š¦^2/2 = š„^2/2 + x + c ć4š¦ ā š¦ć^2/2 = (š„^2+ 2š„ + 2š)/2 4y ā y2 = x2 + 2x + 2c 4y ā y2 = x2 + 2x + r x2 + y2 + 2x ā 4y + r = 0 is general solution