Example 18 - Chapter 3 Class 11 Trigonometric Functions (Term 2)
Last updated at May 29, 2018 by Teachoo
Transcript
Example 18 Find the principal solutions of the equation sin x = √3/2 . sin x = √3/2 We know that sin 60° = √3/2 Here sin is positive, sin is positive in Ist and IInd quadrant Value in Ist quadrant = 60° Value in llnd Quadrant = 180 – 60 = 120° So, principal solution are x = 60° and 120° x = 60/180 𝜋 and 120/180 𝜋 x = 𝜋/3 and 2/3 π
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Chapter 3 Class 11 Trigonometric Functions (Term 2)
Serial order wise
- Ex 3.1
- Ex 3.2
- Ex 3.3
- Ex 3.4
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.