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Last updated at May 29, 2018 by Teachoo
Example 18 Find the principal solutions of the equation sin x = √3/2 . sin x = √3/2 We know that sin 60° = √3/2 Here sin is positive, sin is positive in Ist and IInd quadrant Value in Ist quadrant = 60° Value in llnd Quadrant = 180 – 60 = 120° So, principal solution are x = 60° and 120° x = 60/180 𝜋 and 120/180 𝜋 x = 𝜋/3 and 2/3 π