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  1. Chapter 3 Class 11 Trigonometric Functions
  2. Serial order wise

Transcript

Example 19 Find the principal solutions of the equation tan x = – 1/√3 . tan x = – 1/√3 We know that tan 30° = 1/√3 Since tan x is negative So, x will lie in llnd and lVth Quadrant Value in llnd Quadrant = 180 – 30° Value in lVth Quadrant = 360 – 30° So Principal Solutions are x = 150° x = 150/180 π x = 𝟓/𝟔 π x = 330° x = 330/180 π x = 𝟏𝟏/𝟔 π

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.