
Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Examples
Example 2 Important
Example 3
Example 4
Example 5 Important
Example 6 Important
Example 7 Important
Example 8
Example 9 Important
Example 10
Example 11 Important
Example 12
Example 13
Example 14
Example 15
Example 16 Important
Example 17 Important
Example 18 Important
Example 19
Example 20 Important
Example 21 Important
Example 22 Important
Question 1 Deleted for CBSE Board 2024 Exams
Question 2 Deleted for CBSE Board 2024 Exams You are here
Question 3 Deleted for CBSE Board 2024 Exams
Question 4 Deleted for CBSE Board 2024 Exams
Question 5 Important Deleted for CBSE Board 2024 Exams
Question 6 Deleted for CBSE Board 2024 Exams
Question 7 Important Deleted for CBSE Board 2024 Exams
Last updated at May 29, 2023 by Teachoo
Example 19 Find the principal solutions of the equation tan x = – 1/√3 . tan x = – 1/√3 We know that tan 30° = 1/√3 Since tan x is negative So, x will lie in llnd and lVth Quadrant Value in llnd Quadrant = 180 – 30° Value in lVth Quadrant = 360 – 30° So Principal Solutions are x = 150° x = 150/180 π x = 𝟓/𝟔 π x = 330° x = 330/180 π x = 𝟏𝟏/𝟔 π