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Question 1 Deleted for CBSE Board 2025 Exams
Question 2 Deleted for CBSE Board 2025 Exams
Question 3 Deleted for CBSE Board 2025 Exams
Question 4 Deleted for CBSE Board 2025 Exams
Question 5 Important Deleted for CBSE Board 2025 Exams
Question 6 Deleted for CBSE Board 2025 Exams
Question 7 Important Deleted for CBSE Board 2025 Exams
Last updated at April 16, 2024 by Teachoo
Example 10 Prove that 3sin "π " /6 sec "π " /3 – 4 sin "5π " /6 cot "π " /4 = 1 Solving LHS 3sin "π " /6 sec "π " /3 – 4 sin "5π " /6 cot "π " /4 = 3 × 𝟏/𝟐 × 2 – 4 sin (𝝅 −𝝅/𝟔) × 1 = 3 – 4 sin 𝝅/𝟔 = 3 – 4 × "1 " /2 = 1 = R.H.S.