Example 11 - Find value of sin 15 - Chapter 3 Class 11 - Examples

  1. Chapter 3 Class 11 Trigonometric Functions
  2. Serial order wise
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Example, 11 Find the value of sin 15°. sin 15° = sin (45° – 30°) We know that sin (x – y) = sin x cos y – cos x sin y Hence putting x = 45° y = 30° sin (45° − 30°) = sin 45° cos 30° – cos 45° sin 30° = 1/√2 × √3/2 −1/√2 × 1/2 = 1/√2 ((√3 − 1)/2) = (√3 − 1)/(2√2)

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