Last updated at May 29, 2018 by Teachoo

Transcript

Example 20 Find the solution of sin x = – √3/2 Let sin x = sin y also sin x = (−√3)/2 From (1) and (2) sin y = (−√3)/2 sin y = sin 4/3 π ⇒ y = 4/3 π Step 2 Since sin x = sin y General Solution is x = n π + (–1)n y where n ∈ Z Putting y = 4𝜋/3 x = n π + (–1)n 4/3 π where n ∈ Z

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Chapter 3 Class 11 Trigonometric Functions

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.