Example 22 - Chapter 3 Class 11 Trigonometric Functions
Last updated at Jan. 3, 2020 by Teachoo
Transcript
Example 22 Solve tan 2x = cot (x" + " /3) tan 2x = cot (x" + " /3) We need to make both in terms of tan tan 2x = tan ( /2+x" + " /3) tan 2x = tan ( /2 " + " /3 " + x" ) tan 2x = tan ((3 + 2 )/(2 3) " + x" ) tan 2x = tan (5 /6 " + x" ) General solution tan x = tan y tan 2x = tan 2y From (1) and (2) tan 2y = tan (5 /6 " + x" ) 2y = 5 /6 + x General solution is 2x = n + 2y where n Z put 2y = ("x + " 5 /6) 2x = n + (x + 5 /6) 2x x = n + 5 /6 Hence, x = n + 5 /6 where n Z
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Chapter 3 Class 11 Trigonometric Functions
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.