Subscribe to our Youtube Channel - https://www.youtube.com/channel/UCZBx269Tl5Os5NHlSbVX4Kg
Example 22 - Chapter 3 Class 11 Trigonometric Functions
Last updated at Feb. 13, 2020 by Teachoo
Transcript
Example 22 Solve tan 2x = โ cot (x" + " ๐/3) tan 2x = โcot (๐ฅ" + " ๐/3) We need to make both in terms of tan Rough tan (90ยฐ + ฮธ) = โcot ฮธ โcot ฮธ = tan (90ยฐ + ฮธ) โcot ฮธ = tan (๐/2 " + ฮธ" ) Replacing ฮธ by x + ๐/3 โcot ("x + " ๐/3) = tan (๐/2 "+ x +" ๐/3) tan 2x = tan (๐/2+x" + " ๐/3) tan 2x = tan (๐/2 " + " ๐/3 " + x" ) tan 2x = tan ((3๐ + 2๐)/(2 ร 3) " + x" ) tan 2x = tan (5๐/6 " + x" ) General solution Let tan x = tan y tan 2x = tan 2y From (1) and (2) tan 2y = tan (5๐/6 " + x" ) 2y = 5๐/6 + x General solution is 2x = nฯ + 2y where n โ Z Put 2y = ("x + " 5๐/6) 2x = nฯ + ("x + " 5๐/6) 2x โ x = nฯ + 5๐/6 x = nฯ + ๐๐ /๐ where n โ Z
Examples
Example 1
Example 2
Example 3
Example 4
Example 5 Important
Example 6 Important
Example 7 Important
Example 8
Example 9 Important
Example 10
Example 11 Important
Example 12
Example 13
Example 14
Example 15
Example 16 Important
Example 17 Important
Example 18
Example 19 Important
Example 20
Example 21
Example 22 Important You are here
Example 23
Example 24 Important
Example 25 Important
Example 26 Important
Example 27 Important
Example 28 Important
Example 29 Important
Chapter 3 Class 11 Trigonometric Functions
Serial order wise
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.