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  1. Chapter 3 Class 11 Trigonometric Functions
  2. Serial order wise

Transcript

Example 12 Find the value of tan 13πœ‹/12 tan (13 πœ‹" " )/12 = tan ("Ο€ + " πœ‹/12) = tan πœ‹/12 = tan (πœ‹/4βˆ’πœ‹/6) Using tan (π‘₯ – 𝑦) = (tanπ‘₯ βˆ’ tan⁑y)/(1 + tan π‘₯ tan⁑y ) = (tan⁑〖 Ο€/4γ€— βˆ’ tan Ο€/6)/(1 + tan Ο€/4 tan⁑〖 Ο€/6γ€— ) = (1 βˆ’ 1/√3)/(1 + 1/( √3)) = (√3 βˆ’ 1)/(√3 + 1) = (√3 βˆ’ 1)/(√3 + 1) Γ— (√3 βˆ’ 1)/(√3 βˆ’ 1) = (√(3 )βˆ’ 1)2/(√3 + 1)(√3 βˆ’ 1) = (3 + 1 βˆ’ 2√3)/((√3)2 βˆ’ (1)2) = (4 βˆ’ 2√3)/(3 βˆ’ 1) = 2 – βˆšπŸ‘

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.