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Example 12 - Find value of tan 13pi/12 - Chapter 3 Class 11

Example 12 - Chapter 3 Class 11 Trigonometric Functions - Part 2

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Example 12 Find the value of tan 13πœ‹/12 tan (13 πœ‹" " )/12 = tan ("Ο€ + " πœ‹/12) = tan πœ‹/12 = tan (πœ‹/4βˆ’πœ‹/6) Using tan (π‘₯ – 𝑦) = (tanπ‘₯ βˆ’ tan⁑y)/(1 + tan π‘₯ tan⁑y ) = (tan⁑〖 Ο€/4γ€— βˆ’ tan Ο€/6)/(1 + tan Ο€/4 tan⁑〖 Ο€/6γ€— ) = (1 βˆ’ 1/√3)/(1 + 1/( √3)) = (√3 βˆ’ 1)/(√3 + 1) = (√3 βˆ’ 1)/(√3 + 1) Γ— (√3 βˆ’ 1)/(√3 βˆ’ 1) = (√(3 )βˆ’ 1)2/(√3 + 1)(√3 βˆ’ 1) = (3 + 1 βˆ’ 2√3)/((√3)2 βˆ’ (1)2) = (4 βˆ’ 2√3)/(3 βˆ’ 1) = 2 – βˆšπŸ‘

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.