Last updated at Feb. 13, 2020 by Teachoo
Transcript
Example 12 Find the value of tan 13π/12 tan (13 π" " )/12 = tan ("Ο + " π/12) = tan π/12 = tan (π/4βπ/6) Using tan (π₯ β π¦) = (tanπ₯ β tanβ‘y)/(1 + tan π₯ tanβ‘y ) = (tanβ‘γ Ο/4γ β tan Ο/6)/(1 + tan Ο/4 tanβ‘γ Ο/6γ ) = (1 β 1/β3)/(1 + 1/( β3)) = (β3 β 1)/(β3 + 1) = (β3 β 1)/(β3 + 1) Γ (β3 β 1)/(β3 β 1) = (β(3 )β 1)2/(β3 + 1)(β3 β 1) = (3 + 1 β 2β3)/((β3)2 β (1)2) = (4 β 2β3)/(3 β 1) = 2 β βπ
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