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Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


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Example 12 Find the value of tan 13πœ‹/12 tan (13 πœ‹" " )/12 = tan ("Ο€ + " 𝝅/𝟏𝟐) = tan 𝝅/𝟏𝟐 = 𝒕𝒂𝒏 (𝝅/πŸ’βˆ’π…/πŸ”) Using tan (π‘₯ – 𝑦) = (tanπ‘₯ βˆ’ tan⁑y)/(1 + tan π‘₯ tan⁑y ) = (tan⁑〖 Ο€/4γ€— βˆ’ tan Ο€/6)/(1 + tan Ο€/4 tan⁑〖 Ο€/6γ€— ) = (𝟏 βˆ’ 𝟏/βˆšπŸ‘)/(𝟏 + 𝟏/( βˆšπŸ‘)) = (βˆšπŸ‘ βˆ’ 𝟏)/(βˆšπŸ‘ + 𝟏) = (√3 βˆ’ 1)/(√3 + 1) Γ— (√3 βˆ’ 1)/(√3 βˆ’ 1) = (√(3 )βˆ’ 1)2/(√3 + 1)(√3 βˆ’ 1) = (3 + 1 βˆ’ 2√3)/((√3)2 βˆ’ (1)2) = (4 βˆ’ 2√3)/(3 βˆ’ 1) = 2 – βˆšπŸ‘

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.