Example 12 - Chapter 3 Class 11 Trigonometric Functions

Last updated at June 22, 2023 by Teachoo

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Example 12 Find the value of tan 13𝜋/12 tan (13 𝜋" " )/12 = tan ("π + " 𝝅/𝟏𝟐) = tan 𝝅/𝟏𝟐 = 𝒕𝒂𝒏 (𝝅/𝟒−𝝅/𝟔) Using tan (𝑥 – 𝑦) = (tan𝑥 − tan⁡y)/(1 + tan 𝑥 tan⁡y ) = (tan⁡〖 π/4〗 − tan π/6)/(1 + tan π/4 tan⁡〖 π/6〗 ) = (𝟏 − 𝟏/√𝟑)/(𝟏 + 𝟏/( √𝟑)) = (√𝟑 − 𝟏)/(√𝟑 + 𝟏) = (√3 − 1)/(√3 + 1) × (√3 − 1)/(√3 − 1) = (√(3 )− 1)2/(√3 + 1)(√3 − 1) = (3 + 1 − 2√3)/((√3)2 − (1)2) = (4 − 2√3)/(3 − 1) = 2 – √𝟑

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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