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Example 8 - Chapter 3 Class 11 Trigonometric Functions (Term 2)
Last updated at May 29, 2018 by Teachoo
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Example 8 You are here
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Example 20 Deleted for CBSE Board 2023 Exams
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Chapter 3 Class 11 Trigonometric Functions
Serial order wise
- Ex 3.1
- Ex 3.2
- Ex 3.3
- Ex 3.4
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Examples
- Miscellaneous
Transcript
Example 8 Find the value of sin (31" " π" " )/3 sin 31"π " /3 = sin (10π + 1/3 "π ") = sin (5 × (2π) + 1/3 "π ") = sin (1/3 " π" ) = sin (1/3 " × 180°" ) = sin 60° = √3/2
