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Example 8 - Chapter 3 Class 11 Trigonometric Functions
Last updated at May 29, 2018 by Teachoo
Transcript
Example 8 Find the value of sin (31" " π" " )/3 sin 31"π " /3 = sin (10π + 1/3 "π ") = sin (5 × (2π) + 1/3 "π ") = sin (1/3 " π" ) = sin (1/3 " × 180°" ) = sin 60° = √3/2
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Example 8 You are here
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Example 20 Not in Syllabus - CBSE Exams 2021
Example 21 Not in Syllabus - CBSE Exams 2021
Example 22 Important Not in Syllabus - CBSE Exams 2021
Example 23 Not in Syllabus - CBSE Exams 2021
Example 24 Important Not in Syllabus - CBSE Exams 2021
Example 25 Important
Example 26 Important
Example 27 Important
Example 28 Important
Example 29 Important
Chapter 3 Class 11 Trigonometric Functions
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.