Example 9 - Chapter 3 Class 11 Trigonometric Functions (Term 2)
Last updated at Feb. 13, 2020 by Teachoo
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Chapter 3 Class 11 Trigonometric Functions (Term 2)
Serial order wise
- Ex 3.1
- Ex 3.2
- Ex 3.3
- Ex 3.4
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- Miscellaneous
Transcript
Example 9 Find the value of cos (–1710°). cos(−1710°) = cos(1710°) = cos(1710 ×𝜋/180) = cos(19𝜋/2) = cos(9 1/2 𝜋 ) = cos(10𝜋−𝜋/2) Value of cos x repeats after an interval of 2π, Hence, ignoring 5 × (2π) i.e. 10π = cos((−𝜋)/2) = cos((−180)/2) = cos(–90°) = cos90° = 0 As cos (−x) = cos x
