(sec A + tan A) (1 – sin A) equals:

(a) sec A                        (b) sin A                   (c) cosec A               (d) cos A

This question is similar to Example 10 - Chapter 8 Class 10 Introduction to Trignometry

[Maths Sample Paper] (sec A + tan A) (1 – sin A) equals: (a) sec A - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard

part 2 - Question 12 - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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Transcript

(sec A + tan A)(1 – sin A) We write everything in terms of sin A and cos A = (1/cos⁑〖 𝐴〗 +" " sin⁑〖 𝐴〗/cos⁑〖 𝐴〗 ) (1 – sin A) = ((1 +γ€– sin〗⁑〖 𝐴〗)/cos⁑〖 𝐴〗 )(1 – sin A) = ((1 +γ€– sin〗⁑〖 𝐴) (1 βˆ’γ€– sin〗⁑〖 𝐴)γ€— γ€—)/(cos⁑ 𝐴 ) = ((12 βˆ’γ€– sin^2〗⁑〖 𝐴) γ€—)/( cos⁑〖 𝐴〗 ) = ((𝟏 βˆ’γ€– γ€–π’”π’Šπ’γ€—^πŸγ€—β‘γ€– 𝑨) γ€—)/( 𝒄𝒐𝒔⁑〖 𝑨〗 ) = cos⁑〖2 𝐴〗/( cos⁑〖 𝐴〗 ) = cos A cos2 A + sin2 A = 1 cos2 A = 1 – sin2 A ∴ 1 – sin2 A = cos2 A So, the correct answer is (d)

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