The nature of roots of the quadratic equation 9x^2 – 6x – 2 = 0 is:

 (a) No real roots                                 (b) 2 equal real roots

 (c) 2 distinct real roots                       (d) More than 2 real roots

This question is similar to Ex 4.3, 1 (i) Chapter 4 Class 10 Quadratic Equations

The nature of roots of the quadratic equation 9x^2 – 6x – 2 = 0 is: - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard

part 2 - Question 4 - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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Transcript

9x2 – 6x – 2 = 0 Comparing equation with ax2 + bx + c = 0 a = 9 , b = –6, c = –2 We know that , D = b2 – 4ac = (–6)2 – 4 × 9 × (–2) = 36 + 78 = 114 > 0 Concept: D < 0 , no real roots D = O , two equal real roots D > 0, two distinct real roots Since D > 0 Hence, there are 2 distinct real roots. So, the correct answer is (c)

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