The nature of roots of the quadratic equation 9x^2 – 6x – 2 = 0 is:

 (a) No real roots                                 (b) 2 equal real roots

 (c) 2 distinct real roots                       (d) More than 2 real roots

This question is similar to Ex 4.3, 1 (i) Chapter 4 Class 10 Quadratic Equations

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Transcript

9x2 – 6x – 2 = 0 Comparing equation with ax2 + bx + c = 0 a = 9 , b = –6, c = –2 We know that , D = b2 – 4ac = (–6)2 – 4 × 9 × (–2) = 36 + 78 = 114 > 0 Concept: D < 0 , no real roots D = O , two equal real roots D > 0, two distinct real roots Since D > 0 Hence, there are 2 distinct real roots. So, the correct answer is (c)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.