Question 36 (ii) – Choice 2

When will she be able to achieve a throw of 11.16 m?

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Since, she needs to achieve a throw of 11.16m Given 𝒂_𝒏 = 11.16 m We need to find duration in which she is able to achieve a throw of 11.16 m i.e., we need to find n Now an = a + (n − 1)d Putting a = 7.56, d = 0.09 ,𝑎_𝑛 = 11.16 m 11.16 = 7.56 + (n − 1) × 0.09 11.16 – 7.56 = (n − 1) × 0.09 3.6 = 0.09 × (n – 1) 36/10 = 9/100 × (n – 1) 36/10 × 100/9 = (n – 1) 40 = n – 1 40 + 1 = n n = 41 Hence, Sanjitha will be able to throw 11.16 m after 42 weeks or in 41 weeks

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo