Given that sin θ = a/b, then cos θ is equal to

(A) b/√(b^2  - a^2 )    (B) b/a  

(C) √(b^2  - a^2 )/b    (D) a/√(b^2  - a^2 )

This question is exactly same as Question 7 - NCERT Exemplar - MCQ - Chapter 8 Class 10

Please check https://www.teachoo.com/13507/3604/Question-7/category/NCERT-Exemplar---MCQ/

[Sample Paper] Given that sin θ =a/b, then cos θ is. (a) b/√b^2-a^2 - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard

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