Given that sin θ = a/b, then cos θ is equal to

(A) b/√(b^2  - a^2 )    (B) b/a  

(C) √(b^2  - a^2 )/b    (D) a/√(b^2  - a^2 )

This question is exactly same as Question 7 - NCERT Exemplar - MCQ - Chapter 8 Class 10

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.