Question 36 (ii) – Choice 1

What would be Sanjitha’s throw distance at the end of 6 weeks?

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Our Distance of Throws AP is 7.56, 7.65, 7.74… Now, here Sanjitha’s initial throw distance was 7.56m and she improved the distance by 9 cm every week. Thus, Initial throw distance = 7.56 m Throw distance at end of 1 week = 7.65 m Throw distance at end of 2 weeks = 7.74 m We need to find her throw distance at the end of 6 weeks, i.e. we need to find 𝒂_𝟕 We know that an = a + (n − 1)d Putting n = 7, a = 7.56, d = 0.09 𝑎_7 = 7.56 + (7 − 1) × 0.09 = 7.56 + 6 × 0.09 = 7.56 + 0.54 = 8.1 Hence, Sanjitha’s throw distance at the end of 6 weeks would be 8.1 m

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.