One evening, Kaushik was in a park. Children were playing cricket. Birds were singing on a nearby tree of height 80m. He observed a bird on the tree at an angle of elevation of 45°. When a sixer was hit, a ball flew through the tree frightening the bird to fly away. In 2 seconds, he observed the bird flying at the same height at an angle of elevation of 30° and the ball flying towards him at the same height at an angle of elevation of 60°.

Question 38 (i)

At what distance from the foot of the tree was he observing the bird sitting on the tree?

[Case Based] One evening, Kaushik was in a park. Children were playing - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard

part 2 - Question 38 (i) [Case based] - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

part 3 - Question 38 (i) [Case based] - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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Transcript

We need to find distance of bird from foot of the tree. i.e we need to find CB Here, ∠ ABC = 90Β° In right angle triangle ABC tan C = (𝑆𝑖𝑑𝑒 π‘œπ‘π‘π‘œπ‘ π‘–π‘‘π‘’ π‘‘π‘œ π‘Žπ‘›π‘”π‘™π‘’" " 𝐢)/(𝑆𝑖𝑑𝑒 π‘Žπ‘‘π‘—π‘Žπ‘π‘’π‘›π‘‘ π‘‘π‘œ π‘Žπ‘›π‘”π‘™π‘’" " 𝐢) tan C = (" " 𝐴𝐡)/𝐡𝐢 tan 45Β° = πŸ–πŸŽ/π‘ͺ𝑩 1 = 80/𝐢𝐡 CB = 80 m

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