After hitting the tree, how far did the ball travel in the sky when Kaushik saw the ball?

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Transcript

We need to find Distance the ball travelled after hitting the tree Given that, After hitting the tree, ball flew towards him i.e we need to find FA Now, FA = GB = CB – CG = 80 − CG ∴ We need to find CG In right angle triangle FCG tan C = (𝑆𝑖𝑑𝑒 𝑜𝑝𝑝𝑜𝑠𝑖𝑡𝑒 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝐶)/(𝑆𝑖𝑑𝑒 𝑎𝑑𝑗𝑎𝑐𝑒𝑛𝑡 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝐶) tan C = (" " 𝐹𝐺)/𝐶𝐺 tan 60° = 80/𝐶𝐺 √3 = 80/𝐶𝐺 CG = 𝟖𝟎/√𝟑 m Thus, GB = CB – CG = 80 − 𝟖𝟎/√𝟑 = 80(1 − 𝟏/√𝟑) m

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.