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After hitting the tree, how far did the ball travel in the sky when Kaushik saw the ball?

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We need to find Distance the ball travelled after hitting the tree Given that, After hitting the tree, ball flew towards him i.e we need to find FA Now, FA = GB = CB – CG = 80 βˆ’ CG ∴ We need to find CG In right angle triangle FCG tan C = (𝑆𝑖𝑑𝑒 π‘œπ‘π‘π‘œπ‘ π‘–π‘‘π‘’ π‘‘π‘œ π‘Žπ‘›π‘”π‘™π‘’" " 𝐢)/(𝑆𝑖𝑑𝑒 π‘Žπ‘‘π‘—π‘Žπ‘π‘’π‘›π‘‘ π‘‘π‘œ π‘Žπ‘›π‘”π‘™π‘’" " 𝐢) tan C = (" " 𝐹𝐺)/𝐢𝐺 tan 60Β° = 80/𝐢𝐺 √3 = 80/𝐢𝐺 CG = πŸ–πŸŽ/βˆšπŸ‘ m Thus, GB = CB – CG = 80 βˆ’ πŸ–πŸŽ/βˆšπŸ‘ = 80(1 βˆ’ 𝟏/βˆšπŸ‘) m

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.