Question 38 (ii) (Choice 2) - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at August 6, 2026 by Teachoo

After hitting the tree, how far did the ball travel in the sky when Kaushik saw the ball?

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[Sample Paper] After hitting the tree, how far did the ball travel - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard

part 2 - Question 38 (ii) (Choice 2) - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

part 3 - Question 38 (ii) (Choice 2) - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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Transcript

We need to find Distance the ball travelled after hitting the tree Given that, After hitting the tree, ball flew towards him i.e we need to find FA Now, FA = GB = CB – CG = 80 − CG ∴ We need to find CG In right angle triangle FCG tan C = (𝑆𝑖𝑑𝑒 𝑜𝑝𝑝𝑜𝑠𝑖𝑡𝑒 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝐶)/(𝑆𝑖𝑑𝑒 𝑎𝑑𝑗𝑎𝑐𝑒𝑛𝑡 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝐶) tan C = (" " 𝐹𝐺)/𝐶𝐺 tan 60° = 80/𝐶𝐺 √3 = 80/𝐶𝐺 CG = 𝟖𝟎/√𝟑 m Thus, GB = CB – CG = 80 − 𝟖𝟎/√𝟑 = 80(1 − 𝟏/√𝟑) m

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