Water is flowing at the rate of 15 km/h through a pipe of diameter 14

Let length of pipe for filling whole pond be h m. So, Volume of pipe = Volume of cuboidal pond Volume of pipe Pipe is in form of cylinder where Let Height = h m Diameter = 14 cm So, Radius = 𝐷𝑖𝑎𝑚𝑒𝑡𝑒𝑟/2 = 14/2 = 7 cm = 𝟕/𝟏𝟎𝟎 m Volume of pipe = Volume of cylinder = 𝜋r2h = 𝝅(𝟕/𝟏𝟎𝟎)^𝟐 h = 22/7 × 7/100 × 7/100 × h = (𝟐𝟐 × 𝟕)/𝟏𝟎𝟎𝟎𝟎 h Volume of cuboidal pond Pond is in form cuboid where Length = l = 50 m Breadth = b = 44 m Height = h = 21 cm = 𝟐𝟏/𝟏𝟎𝟎 m Volume of pond = lbh = 50 × 44 × 𝟐𝟏/𝟏𝟎𝟎 = (44\ × 21)/2 = 22 × 21 Now, Volume of pipe = Volume of pond (𝟐𝟐 × 𝟕)/𝟏𝟎𝟎𝟎𝟎h = 22 × 21 h = (22 × 21 × 10000)/(22 × 7) h = 30,000 m h = 30 km Now, Water in pipe flows at rate 15 km/hr So, 15 km travels in pipe in = 1 hour 1 km travels in pipe in = 1/15 hour 30 km travels in pipe in = 30/15 hour = 2 hours So, in 2 hours, the pond will be filled We also need to find the speed of water if the rise in water level is to be attained in 1 hour. We know that Pond takes 2 hours to attain rise at given speed = 15 km/h If it wants to fill in 1 hour, it’s speed should be double Therefore, Speed of water required to attain rise in 1 hour = 15 × 2 = 30 km/h

Question 34 (Choice 1) - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Water is flowing at the rate of 15 km/h through a pipe of diameter 14 cm into a cuboidal pond which is 50 m long and 44 m wide. In what time will the level of water in pond rise by 21 cm? What should be the speed of water if the rise in water level is to be attained in 1 hour

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