Now,
Median = l + (šµ/š āšš)/š Ć h
Since Median = 50
50 ā 60 is Median Class
Where
N = āāšš
l =
h =
cf =
f =
Putting values in formula
Median = l + (šµ/š āšš)/š Ć h
50 = 50 + (šš ā (š + šš))/šš Ć 10
50 = 50 + (5 āš)/2
50 ā 50 = (5 āš)/2
0 = (5 āš)/2
5āš = 0
p = 5
Also,
āāšš = 78 + p + q
Putting values
90 = 78 + 5 + q
90 = 83 + y
90 ā 83 = q
7 = q
q = 7
Hence p = 5, q = 7
Finding Mode
Mode = l + (šš āšš)/(ššš āšš āšš) Ć h
Modal class
= Interval with highest frequency
= 40 ā 50
Here
l = lower limit of modal class = 40
h = class-interval = 50 ā 40 = 10
f1 = frequency of the modal class = 25
f0 = frequency of the class before modal class = 15
f2 = frequency of the class after modal class = 20
Putting these values in formula
ā“ Mode = l + ((š_š ā š_š)/(šš_š ā š_š ā š_š )) Ć h
= 40 + {(šš āšš)/(š Ćšš āšš āšš)} Ć 10
= 40 + 10/(50ā35) Ć 10
= 40 + 100/15
= 40 + 6.67
= 46.67
Made by
Davneet Singh
Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.
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