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Find the value of x if 2cosec^2⁡30+xsin^2⁡60-3/4 tan^2⁡30=10

This question is similar to Question 1,(ii) Ex 8.2, Chapter 8 Class 10

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Transcript

We know that, cosec 30° = 2 sin 60° = √3/2 tan 30° = 1/√3 Now, our equation is 2 cosec^2⁡30+𝑥sin^2⁡60−3/4 tan^2⁡30=10 Putting values 2 × 〖(𝟐)〗^𝟐 + 𝒙 × (√𝟑/𝟐)^𝟐− 𝟑/𝟒 × (𝟏/√𝟑)^𝟐 = 10 8 + 3/4 𝑥 − 1/4 = 10 Multiplying by 4 on both sides 32 + 3𝒙 – 1 = 40 3𝑥 = 40 – 31 3𝑥 = 9 𝒙 = 3

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.