Find the value of x if 2cosec^230+xsin^260-3/4 tan^230=10
This question is similar to Question 1,(ii) Ex 8.2, Chapter 8 Class 10
CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard
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CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard
Last updated at April 16, 2024 by Teachoo
This question is similar to Question 1,(ii) Ex 8.2, Chapter 8 Class 10
We know that, cosec 30° = 2 sin 60° = √3/2 tan 30° = 1/√3 Now, our equation is 2 cosec^230+𝑥sin^260−3/4 tan^230=10 Putting values 2 × 〖(𝟐)〗^𝟐 + 𝒙 × (√𝟑/𝟐)^𝟐− 𝟑/𝟒 × (𝟏/√𝟑)^𝟐 = 10 8 + 3/4 𝑥 − 1/4 = 10 Multiplying by 4 on both sides 32 + 3𝒙 – 1 = 40 3𝑥 = 40 – 31 3𝑥 = 9 𝒙 = 3