Question 23 - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards
Last updated at April 16, 2024 by Teachoo
From an external point P, two tangents, PA and PB are drawn to a circle with centre O . At a point E on the circle, a tangent is drawn to intersect PA and PB at C and D, respectively. If PA = 10 cm, find the perimeter of ∆PCD
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Given PA = 10 cm
We need to find perimeter of ∆PCD
i.e. we need to find PC, PD and CD
From Point A
We know that
Tangent from external point are equal
∴ PA = PB = 10 cm
From Point C
Since Tangent from external point are equal
∴ CA = CE
From Point C
Since Tangent from external point are equal
∴ DB = DE
Now,
Perimeter of ∆PCD = PC + PD + CD
Putting CD = CE + ED
= PC + PD + (CE + ED)
Putting CE = AC, DE = DB
= PC + PD + (AC + DB)
= (PC + AC) + (PD + DB)
= PA + PB
= 10 + 10
= 20 cm
Made by
Davneet Singh
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.
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