CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard

Class 10
Solutions of Sample Papers for Class 10 Boards

## From an external point P, two tangents, PA and PB are drawn to a circle with centre O . At a point E on the circle, a tangent is drawn to intersect PA and PB at C and D, respectively. If PA = 10 cm, find the perimeter of ∆PCD

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### Transcript

Given PA = 10 cm We need to find perimeter of ∆PCD i.e. we need to find PC, PD and CD From Point A We know that Tangent from external point are equal ∴ PA = PB = 10 cm From Point C Since Tangent from external point are equal ∴ CA = CE From Point C Since Tangent from external point are equal ∴ DB = DE Now, Perimeter of ∆PCD = PC + PD + CD Putting CD = CE + ED = PC + PD + (CE + ED) Putting CE = AC, DE = DB = PC + PD + (AC + DB) = (PC + AC) + (PD + DB) = PA + PB = 10 + 10 = 20 cm

#### Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.