There is a square board of side '2a' units circumscribing a red circle. Jayadev asked to keep a dot on the above said board. The probability that he keeps the dot on the shaded region is.
(a) π/4 (b) (4-π)/4 (c) (π - 4)/4 (d) 4/π
CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard
CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard
Last updated at August 2, 2026 by Teachoo
Transcript
Probability of placing a dot on shaded region = (š“ššš šš š āšššš šššššš (ššš¢š))/(ššš”šš šššš) = (šØššš šš šššššš ā šØššš šš šššššš)/(šØššš šš šššššš) Area of square Side = 2a Area = ć(2š)ć^2 =ć ššć^š units Area of circle Radius of circle = 2š/2 = a Area of circle = Ļš^2 Now, Probability of placing a dot on shaded region = (šØššš šš šššššš ā šØššš šš šššššš)/(šØššš šš šššššš) = (4š^2āšš^2)/(4š^2 ) = ((4 ā š ) š^2)/ć 4šć^2 = (4 ā š)/4So, the correct answer is (b)