Question 38 (iii) - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at Dec. 13, 2024 by Teachoo

What is the speed of the bird in m/min if it had flown 20( √ 3 + 1) m?

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Transcript

Given, Distance = 20(√𝟑 + 1)m Time to fly = 2 seconds Now, Speed of bird = (𝐷𝑖𝑠𝑡𝑎𝑛𝑐𝑒 𝑡𝑟𝑎𝑣𝑒𝑙𝑙𝑒𝑑 𝑖𝑛 30 𝑠𝑒𝑐𝑜𝑛𝑑𝑠)/(30 𝑠𝑒𝑐𝑜𝑛𝑑𝑠) = (20(√3 + 1))/2 m/s = 10(√𝟑 + 1) m/s = 10(√3 + 1) × (1 𝑚𝑒𝑡𝑒𝑟)/(1 𝑠𝑒𝑐𝑜𝑛𝑑) = 10(√3 + 1) × (𝟏 𝒎𝒆𝒕𝒆𝒓)/(𝟏/𝟔𝟎 𝒎𝒊𝒏𝒖𝒕𝒆𝒔) = 10(√3 + 1) × 60/1 m/min = 600(√𝟑 + 1) m/min

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo

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