If a pole 6 m high casts a shadow 2√3m long on the ground, then the Sun’s elevation is
(a) 60° (b) 45° (c) 30° (d) 90°
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CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard
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CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard
Last updated at April 16, 2024 by Teachoo
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Given Height of pole = DE = 6 m Length of shadow = EF = 2βπm We need to find Angle of elevation of the sun i.e π In β π·πΈπΉ tan π = (ππππ πππππ ππ‘π π‘π πππππ" " πΉ)/β(ππππ ππππππππ‘ π‘π πππππ" " πΉ@ ) tan π½ = (" " π«π¬)/π¬π tan π = (" " 6)/(2β3) tan π = (" " 3)/β3 tan π =β3 β΄ π½ = 60 Β° So, the correct answer is (a)