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Example 13 - Chapter 8 Class 10 Introduction to Trignometry (Term 1)

Last updated at Dec. 24, 2019 by

Example 13 - Prove that sec A (1 - sin A)(sec A + tan A) = 1 - Examples

Example 13 - Chapter 8 Class 10 Introduction to Trignometry - Part 2

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Example 13 Prove that sec A (1 sin A)(sec A + tan A) = 1. Solving L.H.S sec A (1 sin A) (sec A + tan A) We write everything in terms of sin A and cos A = 1/cos (1 sin A) (" " 1/cos +" " sin /cos ) = ((1 sin ) )/(cos ) (" " (1 + sin )/cos ) = ((1 sin ) (1+ sin ) )/(cos cos ) We know that (a b) (a + b) = a2 b2 = ((12 sin2 ) )/( cos 2 ) = ((1 sin2 ) )/( cos 2 ) = ( 2 )/(cos2 ) = 1 = R.H.S Thus, L.H.S = R.H.S Hence proved

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