Get live Maths 1-on-1 Classs - Class 6 to 12
Example 13 - Chapter 8 Class 10 Introduction to Trignometry (Term 1)
Last updated at March 22, 2023 by Teachoo
Examples
Example 1
Example 2 Important
Example 3
Example 4
Example 5 Important
Example 6
Example 7 Important
Example 8 Important
Example 9 Deleted for CBSE Board 2023 Exams
Example 10 Important Deleted for CBSE Board 2023 Exams
Example 11 Important Deleted for CBSE Board 2023 Exams
Example 12
Example 13 Important You are here
Example 14 Important
Example 15 Important
Chapter 8 Class 10 Introduction to Trignometry
Serial order wise
Transcript
Example 13 Prove that sec A (1 sin A)(sec A + tan A) = 1. Solving L.H.S sec A (1 sin A) (sec A + tan A) We write everything in terms of sin A and cos A = 1/cos (1 sin A) (" " 1/cos +" " sin /cos ) = ((1 sin ) )/(cos ) (" " (1 + sin )/cos ) = ((1 sin ) (1+ sin ) )/(cos cos ) We know that (a b) (a + b) = a2 b2 = ((12 sin2 ) )/( cos 2 ) = ((1 sin2 ) )/( cos 2 ) = ( 2 )/(cos2 ) = 1 = R.H.S Thus, L.H.S = R.H.S Hence proved
