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Example 10 - If sin 3A = cos (A - 26), find value of A - Trignometric ratios of complementry angles

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Example 10 If sin 3A = cos (A – 26°), where 3A is an acute angle, find the value of A. Given that, sin 3A = cos (A – 26°) cos (90° – 3A) = cos (A − 26°) Comparing angles 90 – 3A = A − 26° − 3A – A = – 26 – 90 − 4A = − 116 A = (−116)/(−4) A = 29 Hence, A = 29°

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.