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Example 7 - Chapter 8 Class 10 Introduction to Trignometry (Term 1)
Last updated at March 22, 2023 by Teachoo
Examples
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Example 7 Important You are here
Example 8 Important
Example 9 Deleted for CBSE Board 2023 Exams
Example 10 Important Deleted for CBSE Board 2023 Exams
Example 11 Important Deleted for CBSE Board 2023 Exams
Example 12
Example 13 Important
Example 14 Important
Example 15 Important
Chapter 8 Class 10 Introduction to Trignometry
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Transcript
Example 7 In Δ PQR, right-angled at Q (see Fig. ), PQ = 3 cm and PR = 6 cm. Determine ∠ QPR and ∠ PRQ. Given data, PQ = 3 cm PR = 6 cm Now, sin R = (𝑠𝑖𝑑𝑒 𝑜𝑝𝑝𝑜𝑠𝑖𝑡𝑒 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒 𝑅)/𝐻𝑦𝑝𝑜𝑡𝑒𝑛𝑢𝑠𝑒 sir R = 𝑃𝑄/𝑃𝑅 sir R = 3/6 sin R = 1/2 sin R = sin 30° R = 30° So, ∠ PRQ = 30° We know that, ∠ P + ∠ Q + ∠ R = 180° ∠ P + 90° + 30° = 180° ∠ P + 120° = 180° ∠ P = 180° - 120° ∠ P = 60° So, ∠ QPR = 60° Hence , ∠ PRQ = 30° ∠ QPR = 60°
