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Last updated at Sept. 24, 2018 by Teachoo

Transcript

Example 12 Express the ratios cos A, tan A and sec A in terms of sin A. cos A Since, cos2 A + sin2 A = 1 cos2 A = 1 β sin2 A cos A = Β±β(1 βπ ππ2 π΄) Here, A is acute (i.e. less than 90Β°) & cos A is positive when A is acute So, cos A = β(1 βπ ππ2 π΄) sec A sec A = π/ππ¨π¬β‘γ π¨γ sec A = 1/β(1 βπ ππ2 π΄) tan A We know that tan A = πππβ‘γ π¨γ/πππβ‘γ π¨γ Putting value of cos A tan A = sinβ‘γ π΄γ/β(1 β π ππ2 π΄)

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Example 9 Deleted for CBSE Board 2022 Exams

Example 10 Important Deleted for CBSE Board 2022 Exams

Example 11 Important Deleted for CBSE Board 2022 Exams

Example 12 You are here

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Example 15 Important

Chapter 8 Class 10 Introduction to Trignometry (Term 1)

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.