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Example 12 - Chapter 8 Class 10 Introduction to Trignometry (Term 1)
Last updated at Sept. 24, 2018 by Teachoo
Transcript
Example 12 Express the ratios cos A, tan A and sec A in terms of sin A. cos A Since, cos2 A + sin2 A = 1 cos2 A = 1 β sin2 A cos A = Β±β(1 βπ ππ2 π΄) Here, A is acute (i.e. less than 90Β°) & cos A is positive when A is acute So, cos A = β(1 βπ ππ2 π΄) sec A sec A = π/ππ¨π¬β‘γ π¨γ sec A = 1/β(1 βπ ππ2 π΄) tan A We know that tan A = πππβ‘γ π¨γ/πππβ‘γ π¨γ Putting value of cos A tan A = sinβ‘γ π΄γ/β(1 β π ππ2 π΄)
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Example 2 Important
Example 3
Example 4
Example 5 Important
Example 6
Example 7 Important
Example 8 Important
Example 9 Deleted for CBSE Board 2022 Exams
Example 10 Important Deleted for CBSE Board 2022 Exams
Example 11 Important Deleted for CBSE Board 2022 Exams
Example 12 You are here
Example 13 Important
Example 14 Important
Example 15 Important
Chapter 8 Class 10 Introduction to Trignometry (Term 1)
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.