
Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Examples
Example 2 Important
Example 3
Example 4
Example 5 Important
Example 6
Example 7 Important
Example 8 Important
Example 9 You are here
Example 10 Important
Example 11 Important
Example 12 Important
Question 1 Deleted for CBSE Board 2024 Exams
Question 2 Important Deleted for CBSE Board 2024 Exams
Question 3 Important Deleted for CBSE Board 2024 Exams
Last updated at May 29, 2023 by Teachoo
Example 9 Express the ratios cos A, tan A and sec A in terms of sin A. cos A Since, cos2 A + sin2 A = 1 cos2 A = 1 โ sin2 A cos A = ยฑโ(1 โ๐ ๐๐2 ๐ด) Here, A is acute (i.e. less than 90ยฐ) & cos A is positive when A is acute So, cos A = โ(1 โ๐ ๐๐2 ๐ด) sec A sec A = ๐/๐๐จ๐ฌโกใ ๐จใ sec A = 1/โ(1 โ๐ ๐๐2 ๐ด) tan A We know that tan A = ๐๐๐โกใ ๐จใ/๐๐๐โกใ ๐จใ Putting value of cos A tan A = sinโกใ ๐ดใ/โ(1 โ ๐ ๐๐2 ๐ด)