Last updated at Dec. 28, 2018 by Teachoo

Transcript

Example 1 Given tan A = 4/3 , find the other trigonometric ratios of the angle A Given, tan A = 4/3 (π πππ πππππ ππ‘π π‘π πππππ π΄)/(π πππ ππππππππ‘ π‘π πππππ π΄) = 4/3 π΅πΆ/π΄π΅ = 4/3 Let BC = 4x AB = 3x We find AC using Pythagoras Theorem In right triangle ABC Using Pythagoras theorem (Hypotenuse)2 = (Height)2 + (Base)2 (AC)2 = (BC)2 + (AB)2 (AC)2 = (4x)2 + (3x)2 (AC)2 = 16x2 + 9x2 (AC)2 = 25x2 AC = β25π₯2 AC = 5x Now, sin A = (π πππ πππππ ππ‘π π‘π πππππ π΄)/π»π¦πππ‘πππ’π π sin A = π΅πΆ/π΄πΆ sin A = 4π₯/5π₯ Sin A = 4/5 Similarly, cos A = (π πππ ππππππππ‘ π‘π π΄)/π»π¦πππ‘πππ’π π cos A = π΄π΅/π΄πΆ cos A = 3π₯/5π₯ cos A = 3/5 Given, tan A=4/3 cosec A = 1/sinβ‘π΄ = 1/(4/5) = 5/4 sec A = 1/cosβ‘γ π΄γ = 1/((3/5) ) = 5/3 cot A = 1/tanβ‘π΄ = 1/(4/3) = 3/4

Examples

Example 1
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Example 2 Important

Example 3

Example 4

Example 5

Example 6 Important

Example 7 Important

Example 8

Example 9 Deleted for CBSE Board 2022 Exams

Example 10 Important Deleted for CBSE Board 2022 Exams

Example 11 Important Deleted for CBSE Board 2022 Exams

Example 12

Example 13 Important

Example 14 Important

Example 15 Important

Chapter 8 Class 10 Introduction to Trignometry (Term 1)

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.