Given that sin θ = a/b, then cos θ is equal to

(A) b/√(b^2  - a^2 )    (B) b/a  

(C) √(b^2  - a^2 )/b    (D) a/√(b^2  - a^2 )

This question is exactly same as Question 7 - NCERT Exemplar - MCQ - Chapter 8 Class 10

Please check https://www.teachoo.com/13507/3604/Question-7/category/NCERT-Exemplar---MCQ/

[Sample Paper] Given that sin θ =a/b, then cos θ is. (a) b/√b^2-a^2 - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo