The nature of roots of the quadratic equation 9x^2 – 6x – 2 = 0 is:

 (a) No real roots                                 (b) 2 equal real roots

 (c) 2 distinct real roots                       (d) More than 2 real roots

This question is similar to Ex 4.3, 1 (i) Chapter 4 Class 10 Quadratic Equations

The nature of roots of the quadratic equation 9x^2 – 6x – 2 = 0 is: - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard

part 2 - Question 4 - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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9x2 – 6x – 2 = 0 Comparing equation with ax2 + bx + c = 0 a = 9 , b = –6, c = –2 We know that , D = b2 – 4ac = (–6)2 – 4 × 9 × (–2) = 36 + 78 = 114 > 0 Concept: D < 0 , no real roots D = O , two equal real roots D > 0, two distinct real roots Since D > 0 Hence, there are 2 distinct real roots. So, the correct answer is (c)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo