Example 37 - Chapter 13 Class 12 Probability
Last updated at May 29, 2018 by Teachoo
Transcript
Example 37 If a machine is correctly set up, it produces 90% acceptable items. If it is incorrectly set up, it produces only 40% acceptable items. Past experience shows that 80% of the set ups are correctly done. If after a certain set up, the machine produces 2 acceptable items, find the probability that the machine is correctly setup. Let E1 : Event that the machine is correctly setup E2 : Event that the machine is incorrectly setup A : Event that the Machine produce two acceptable items We need to find out the probability that the machine have a correct set up if it produce two acceptable item i.e. P(E1|A) P(E1|A) = 𝑃 𝐸1.𝑃(𝐴| 𝐸1)𝑃 𝐸1.𝑃(𝐴| 𝐸1)+𝑃 𝐸2.𝑃(𝐴| 𝐸2) Putting values in the formula P(E1|A) = 𝑃 𝐸1.𝑃(𝐴| 𝐸1)𝑃 𝐸1.𝑃(𝐴| 𝐸1)+𝑃 𝐸2.𝑃(𝐴| 𝐸2) = 0.8 × 𝟎.𝟖𝟏0.8 × 𝟎.𝟖𝟏 + 0.2 × 𝟎.𝟏𝟔 = 0.6480.680 = 0.95
Examples
Example 1
Example 2
Example 3
Example 4
Example 5
Example 6 Important
Example 7 Important
Example 8
Example 9
Example 10
Example 11 Important
Example 12
Example 13
Example 14
Example 15
Example 16
Example 17 Important
Example 18 Important
Example 19
Example 20 Important
Example 21 Important
Example 22
Example 23
Example 24
Example 25 Important
Example 26 Important
Example 27 Important
Example 28 Important
Example 29 Important
Example 30
Example 31 Important
Example 32 Important
Example 33
Example 34
Example 35 Important
Example 36 Important
Example 37 You are here
Chapter 13 Class 12 Probability
Serial order wise
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.